Tích phân \(\displaystyle\int\limits_1^2\dfrac{\mathrm{\,d}x}{2x+1}\) bằng
\(\log\dfrac{5}{3}\) | |
\(\dfrac{2}{15}\) | |
\(\dfrac{1}{2}\ln\dfrac{5}{3}\) | |
\(\dfrac{16}{225}\) |
Chọn phương án C.
Dùng máy tính cầm tay ta có \(\displaystyle\int\limits_1^2\dfrac{\mathrm{\,d}x}{2x+1}\approx0,2554\ldots\)
Và \(\dfrac{1}{2}\ln\dfrac{5}{3}\approx0,2554\ldots\)
Chọn phương án C.
\(\begin{align*}\displaystyle\int\limits_1^2\dfrac{\mathrm{\,d}x}{2x + 1}&= \dfrac{1}{2}\ln(2x+1)\bigg|_1^2\\
&=\dfrac{1}{2}(\ln5-\ln3)= \dfrac{1}{2}\ln\dfrac{5}{3}.\end{align*}\)