Với \(a\neq0\). Cho biểu thức \(B=\displaystyle\int\limits_{-1}^{1}ax^2\mathrm{\,d}x\). Khẳng định nào sau đây sai?
\(B=a\displaystyle\int\limits_{-1}^{1}x^2\mathrm{\,d}x\) | |
\(B=-\displaystyle\int\limits_{1}^{-1}ax^2\mathrm{\,d}x\) | |
\(B=\displaystyle\int\limits_{1}^{0}ax^2\mathrm{\,d}x+\displaystyle\int\limits_{0}^{-1}ax^2\mathrm{\,d}x\) | |
\(B=\dfrac{2a}{3}\) |
Chọn phương án C.
\(\displaystyle\int\limits_{1}^{0}ax^2\mathrm{\,d}x+\displaystyle\int\limits_{0}^{-1}ax^2\mathrm{\,d}x=\displaystyle\int\limits_{1}^{-1}ax^2\mathrm{\,d}x=-B\).