Chọn phương án D.

Ta thấy \(M(0;5;0)\in(P)\).

Vì \(\dfrac{2}{2}=\dfrac{-1}{-1}=\dfrac{3}{3}\neq\dfrac{5}{1}\) nên \((P)\parallel(P)\).

Do đó $$\begin{aligned}
\mathrm{d}\left((P),(Q)\right)&=\mathrm{d}\left(M,(Q)\right)\\
&=\dfrac{\left|2\cdot0-(-5)+3\cdot0+1\right|}{\sqrt{2^2+(-1)^2+3^2}}\\
&=\dfrac{4}{\sqrt{14}}.
\end{aligned}$$