Giới hạn \(\lim\limits_{x\to-1}\dfrac{\sqrt{3x^2+1}-x}{x-1}\) bằng
\(-\dfrac{3}{2}\) | |
\(\dfrac{1}{2}\) | |
\(-\dfrac{1}{2}\) | |
\(\dfrac{3}{2}\) |
Chọn phương án A.
\(\begin{aligned}\lim\limits_{x\to-1}\dfrac{\sqrt{3x^2+1}-x}{x-1}&=\dfrac{\sqrt{3(-1)^2+1}-(-1)}{-1-1}\\
&=-\dfrac{3}{2}.\end{aligned}\)