Tính \(\lim\limits_{x\to2}\dfrac{\sqrt[3]{3x^2-4}-\sqrt{3x-2}}{x+1}\).
![]() | \(-\dfrac{3}{2}\) |
![]() | \(-\dfrac{2}{3}\) |
![]() | \(0\) |
![]() | \(+\infty\) |
Chọn phương án C.
\(\lim\limits_{x\to2}\dfrac{\sqrt[3]{3x^2-4}-\sqrt{3x-2}}{x+1}=\dfrac{\sqrt[3]{3\cdot2^2-4}-\sqrt{3\cdot2-2}}{2+1}=0\).