Cho hai vectơ \(\vec{a}\) và \(\vec{b}\). Đẳng thức nào sau đây đúng?
![]() | \(\sqrt{\left(\vec{a}\right)^2}=\vec{a}\) |
![]() | \(\vec{a}=\pm\left|\vec{a}\right|\) |
![]() | \(\sqrt{\left(\vec{a}\right)^2}=\left|\vec{a}\right|\) |
![]() | \(\left|\vec{a}\cdot\vec{b}\right|=\left|\vec{a}\right|\cdot\left|\vec{b}\right|\) |
Chọn phương án C.
\(\begin{aligned}\left(\vec{a}\right)^2&=\vec{a}\cdot\vec{a}\\
&=\left|\vec{a}\right|\cdot\left|\vec{a}\right|\cdot\cos\left(\vec{a},\vec{a}\right)\\
&=\left|\vec{a}\right|^2\cos0^\circ\\
&=\left|\vec{a}\right|^2.\end{aligned}\)
Suy ra \(\sqrt{\left(\vec{a}\right)^2}=\left|\vec{a}\right|\).