Tích phân \(\displaystyle\int\limits_{1}^{2}\dfrac{\mathrm{d}x}{2x+3}\) bằng
\(\dfrac{1}{2}\ln\dfrac{7}{5}\) | |
\(\ln\dfrac{7}{5}\) | |
\(2\ln\dfrac{7}{5}\) | |
\(\dfrac{1}{2}\ln35\) |
Chọn phương án A.
\(\begin{aligned}\displaystyle\int\limits_{1}^{2}\dfrac{\mathrm{d}x}{2x+3}&=\dfrac{1}{2}\ln|2x+3|\bigg|_1^2=\dfrac{1}{2}\left(\ln7-\ln5\right)\\ &=\dfrac{1}{2}\ln\dfrac{7}{5}.\end{aligned}\)