Cho $\displaystyle\displaystyle\int\limits_{4}^{9}f(x)\mathrm{d}x=10$. Tính tích phân $J=\displaystyle\displaystyle\int\limits_{0}^{1}f(5x+4)\mathrm{d}x$.
$J=2$ | |
$J=10$ | |
$J=50$ | |
$J=4$ |
Chọn phương án A.
Đặt $u=5x+4\Rightarrow\mathrm{d}u=5\mathrm{d}x\Rightarrow\mathrm{d}x=\dfrac{1}{5}\mathrm{d}u$.
Vậy $J=\displaystyle\int\limits_{4}^{9}f(x)\cdot\dfrac{1}{5}\mathrm{d}x=\dfrac{10}{5}=2$.