Nếu $\displaystyle\displaystyle\int\limits_0^2f(x)\mathrm{\,d}x=4$ thì $\displaystyle\displaystyle\int\limits_0^23f(x)\mathrm{\,d}x$ bằng
![]() | $36$ |
![]() | $12$ |
![]() | $3$ |
![]() | $4$ |
Chọn phương án B.
Ta có $\displaystyle\int\limits_0^23f(x)\mathrm{\,d}x=3\displaystyle\int\limits_0^2f(x)\mathrm{\,d}x=3\cdot4=12$.