Nếu $\displaystyle\displaystyle\int\limits_0^2f(x)\mathrm{\,d}x=5$ thì $\displaystyle\displaystyle\int\limits_0^2[2f(x)-1]\mathrm{\,d}x$ bằng
![]() | $8$ |
![]() | $9$ |
![]() | $10$ |
![]() | $13$ |
Chọn phương án A.
$\displaystyle\int\limits_0^2[2f(x)-1]\mathrm{\,d}x=2\displaystyle\int\limits_0^2f(x)\mathrm{\,d}x-\displaystyle\int\limits_0^2\mathrm{\,d}x=2\cdot5-x\bigg|_0^2=8$.