Tính tích phân \(I=\displaystyle\int\limits_0^{\tfrac{\pi}{2}}\left(\sin{2x}+\sin x\right)\mathrm{\,d}x\).
\(5\) | |
\(3\) | |
\(4\) | |
\(2\) |
Chọn phương án D.
\(\begin{aligned}I&=\displaystyle\int\limits_0^{\tfrac{\pi}{2}}\left(\sin{2x}+\sin x\right)\mathrm{\,d}x\\
&=\left(-\dfrac{1}{2}\cos2x-\cos x\right)\bigg|_0^{\tfrac{\pi}{2}}\\
&=2.\end{aligned}\)