Tích phân \(\displaystyle\int\limits_0^13^{2x+1}\mathrm{\,d}x\) bằng
\(\dfrac{27}{\ln9}\) | |
\(\dfrac{9}{\ln9}\) | |
\(\dfrac{4}{\ln3}\) | |
\(\dfrac{12}{\ln3}\) |
Chọn phương án D.
\(\displaystyle\int\limits_0^1 3^{2x+1}\mathrm{\,d}x=\dfrac{1}{2}\cdot\dfrac{3^{2x+1}}{\ln 3}\bigg|_0^1=\dfrac{12}{\ln3}\).