Giải phương trình $\sin\big(x-10^\circ\big)=\dfrac{\sqrt{3}}{2}$.
$\left[\begin{array}{l}x=70^\circ+k360^\circ\\ x=-70^\circ+k360^\circ\end{array}\right.$ | |
$\left[\begin{array}{l}x=70^\circ+k360^\circ\\ x=130^\circ+k360^\circ\end{array}\right.$ | |
$\left[\begin{array}{l}x=70^\circ+k360^\circ\\ x=130^\circ+k180^\circ\end{array}\right.$ | |
$\left[\begin{array}{l}x=60^\circ+k360^\circ\\ x=120^\circ+k360^\circ\end{array}\right.$ |
Chọn phương án B.
$\begin{aligned}
\sin\big(x-10^\circ\big)=\dfrac{\sqrt{3}}{2}&\Leftrightarrow\left[\begin{array}{l}x-10^\circ=60^\circ+k360^\circ\\ x-10^\circ=120^\circ+k360^\circ\end{array}\right.\\
&\Leftrightarrow\left[\begin{array}{l}x=70^\circ+k360^\circ\\ x=130^\circ+k360^\circ\end{array}\right.\,(k\in\mathbb{Z})
\end{aligned}$