Cho tam giác đều \(ABC\) cạnh \(a\). Tìm mệnh đề đúng.
![]() | \(\left|\overrightarrow{AB}\right|+\left|\overrightarrow{AC}\right|=a\) |
![]() | \(\left|\overrightarrow{AB}\right|+\left|\overrightarrow{AC}\right|=a\sqrt{3}\) |
![]() | \(\left|\overrightarrow{AB}\right|+\left|\overrightarrow{AC}\right|=\dfrac{a\sqrt{3}}{2}\) |
![]() | \(\left|\overrightarrow{AB}\right|+\left|\overrightarrow{AC}\right|=2a\) |
Chọn phương án D.
Ta có \(\left|\overrightarrow{AB}\right|=\left|\overrightarrow{AC}\right|=a\) nên \(\left|\overrightarrow{AB}\right|+\left|\overrightarrow{AC}\right|=2a\).